program explanation ?

Question

Hi

Can anyone walk me through the code ..

What does this actually script display?

if in-case any error please correct those :)

x=3;

y=5;

i=2;

z=[4 5 2 6 3];

disp('start')

while i<=6

if (i>5)

disp('done')

elseif (i>3 &i~=5)

back1=confuse2(i,x,y,z);

back1=back1/z(i)

end

i=i+1;

end

function out1=confuse3(j,d,s,k)

switch (k(j))

case {1,2}

out1=d+5

case {3,4}

out1=2*s

otherwise

out1=d+j*j+2*s

end

function out2=confuse2(j,y,x,k)

temp=[1 1 1 1 1];

for i=j:5

temp(i)=k(i)+k(j);

end

out2=sum(temp)

The answer should be:

start

out2 = 24

back1 =4

done

Cheers mate ...

TY for support

Vulpes · Answer

This is actually a MATLAB rather than a VB script. After initializing the scalar variables x y i and the array z the script then displays the string 'start'. A while loop is then entered which increments i on each iteration until i reaches 6. Nothing happens until i reaches 4 when the condition i >3 and i ~= 5 (not equals 5) is satisfied. The function confuse2 is then called with the following arguments: j = 4 y = 3 x = 5 k = [4 5 2 6 3] The for statement within that function then runs for i= j to 5 i.e. from 4 to 5. temp(4) is set to 6 + 6 = 12 temp(5) is set to 3 + 6 = 9 out2 is then set to the sum of the elements of temp (1 + 1 + 1 + 12 + 9 = 24). As this line isn't followed by a semi-colon (which suppresses output) the following gets output to the command window: out2 = 24 Back in the while loop back1 is set to the result of the function call (i.e 24). This is then divided by z(4) which is 6 giving a result of 4. As there's no semi-colon the following gets printed to the command window: back1 = 4 i is then incremented to 5 and the while loop does nothing. However when i is finally incremented to 6 the string 'done' is displayed.