Wanted to create a dynamic table with 4 columns in a row

Question

In a master page I am trying to create a dynamic table with 4 columns for a table row. Actual my requirement is I have text box in which I will give a number basing on that number input it should create 4 column's in a row ex: in my text box i/p is 5 then table should created in the below format Label1 TetBox1 Label2 TextBox2 Label3 TextBox3 Label4 TextBox4 Label5 TextBox5 in this first column Level1 and textbox1 in 2nd column in the same way third column and fourth column's level2 and textbox2 in the above mentioned format my dynamic table should be created. I have tried but recieving an error. Help is needed ASAP As I stuck with this functionality

ali tuncer · Answer

Now you are creating a table with id tabletxtRoundNumber in server side with this line: table = new Table(); table.ID = table + chosenDropDown.ID; Page.Form.Controls.Add(table); Initially you were trying to find a table with id tabletxtRoundNumber this way but it didn't exist.. Table table = // new Table(); (Table)Page.Form.FindControl(table + chosenDropDown.ID); Anyway I am glad it is working now..

Phani Kumar · Answer

Yes the functionality is working I have placed a panel but I am not adding this table to that panel now I added it it is displaying fine. Thanks for your help. Here is my part of code protected void txtRoundNumber_TextChanged(object sender EventArgs e) { TextBox chosenDropDown = (TextBox)sender; Int32 pickedValue = Int32.Parse(chosenDropDown.Text); table = new Table(); table.ID = table + chosenDropDown.ID; Page.Form.Controls.Add(table); //(Table)Page.Form.FindControl(table); //table.ID = table + chosenDropDown.ID; for (int i = 1; i { TableRow row = new TableRow(); TableCell cell = new TableCell(); cell.Attributes.Add(runat server); Label txtLevel = new Label(); txtLevel.ID = txtLevel + i.ToString(); txtLevel.Text = Level + i.ToString()+ ; txtLevel.EnableViewState = true; cell.Controls.Add(txtLevel); TextBox txtInterview = new TextBox(); txtInterview.ID = txtLevel_ + i.ToString(); txtInterview.Text = ; txtInterview.EnableViewState = true; cell.Controls.Add(txtInterview); row.Cells.Add(cell); table.Rows.Add(row); } pnlInterview.Visible = true; pnlInterview.Controls.Add(table); }

ali tuncer · Answer

could be related to css or you might be creating them in a wrong place(could be wrong divtabletd..) if functionality is working that part should be easier!

Phani Kumar · Answer

Hi Ali I have modified my part of code then it worked but here I got another problem is text boxes which were given dynamic those were displayed in the bottom of page they are not coming in the part where i wanted them

ali tuncer · Answer

Hi Phani I didn't realize you were using master page it is looking for a table in master page.. you don't need that line you already defined a table with id table in aspx code..delete that line it will build..

Phani Kumar · Answer

Hi Ali I have modified the mentioned as suggested by you but it doesn't worked still getting null value for table

Phani Kumar · Answer

but we need to give id for table how to give it then

ali tuncer · Answer

Hi Phani That's the problem you are trying to add rows to a table with id tabletxtRoundNumber in your page but it doesn't exist. You need to fix that part..you should look for a table id that exist in the page..

Phani Kumar · Answer

Hi Ali it is returning null

Amit Kumar · Answer

Hi Dear Please open this link In hope your problem will resolve.. http://www.dotnetcurry.com/ShowArticle.aspx?ID=135

ali tuncer · Answer

What does this line return? is it null? Probably this part has problem.. Table table = // new Table(); (Table)Page.Form.FindControl(table + chosenDropDown.ID); if you change like this I don't think you will receive object reference not set to an object error: Table table = // new Table(); (Table)Page.Form.FindControl(table);

Phani Kumar · Answer

Hi Lizard Here I am adding my piece of code In aspx.cs page : protected void txtRoundNumber_TextChanged(object sender EventArgs e) { TextBox chosenDropDown = (TextBox)sender; Int32 pickedValue = Int32.Parse(chosenDropDown.Text); Table table = // new Table(); (Table)Page.Form.FindControl(table + chosenDropDown.ID); for (int i = 0; i { TableRow row = new TableRow(); TableCell cell = new TableCell(); TableCell cell1 = new TableCell(); //cell1.Attributes.Add(runat server); cell.Attributes.Add(runat server); Label txtLevel = new Label(); TextBox txtInterview = new TextBox(); txtLevel.ID = txtLevel + i.ToString(); txtLevel.Text = InterviewLevel + i.ToString(); txtLevel.EnableViewState = true; txtInterview.ID = txtLevel_ + i.ToString(); //txtInterview.Text = ; txtInterview.EnableViewState = true; //cell1.Controls.Add(txtLevel); cell.Controls.Add(txtInterview); row.Cells.Add(cell); //row.Cells.Add(cell1); table.Rows.Add(row); } } In aspx. page : * CssClass=failureNotification ErrorMessage=Please Select Module ValidationGroup=IRM ForeColor=Red>  * CssClass=failureNotification ErrorMessage=Please Enter Number of Rounds of Interview ValidationGroup=IRM ForeColor=Red>  I am unable to know where I went wrong

Phani Kumar · Answer

i don't want 5 rows of text boxes My form is interview round configuration Here I will enter number of rounds of interview then I need to display dynamic text boxes with label as level1 opp to that user can enter 1st level interview round name in text box. in this format what was the user enter the number that many text boxes to be displayed with level numbers.

Phani Kumar · Answer

Hi Lizard thanks for your reply the error which I am getting is while adding row to table then I am getting object reference not set to an object I am getting NULL reference there

theLizard · Answer

You have not told us what the error is so can only guess. You have not told us if the text box is an asp:TextBox or a plain Input TextBox. You have not told us what you want to do with the text boxes after they are created. The following is a simple implementation of what you want In Master Page Code file protected void Button1_Click(object sender EventArgs e) { int boxes=0 rows = 0 i=0 t=1 perrow = 0 k=0; decimal j = 0; int.TryParse(TextBox2.Text out perrow); int.TryParse(TextBox1.Text out boxes); string s =  ; j = boxes; if ( j % perrow != 0) { rows = (int)j/perrow + 1; } else rows = (int)j / perrow; for (i = 0; i { s +=  ; for (k = 0; k { s = AddRow(s t); t++; boxes--; if (boxes == 0) break; } if (k % perrow == 0) s +=  ; } s +=  ; TableDiv.InnerHtml = s; } private string AddRow(string s int t) { s +=  Label + t.ToString() +  ; s +=  ; return (s); } In Master Page .auto-style1 { width: 139px; } Num Text Boxes Text Boxes each Row

Label1	TetBox1	Label2	TextBox2
Label3	TextBox3	Label4	TextBox4
Label5	TextBox5